Composition of Relations
Tags: discrete math
Find \(S \circ R\) if \(R = \{(1,1),(1,2),(2,5),(3,4)\}\) and \(S = \{(1,6),(2,1),(4,0)\}\)
\[S \circ R = \{(1,6),(1,1),(3,0)\}\]because (1,1)[1] == (1,6)[0], we get ((1,1)[0], (1,6)[1]) == (1,6)
because (1,2)[1] == (2,1)[0], we get ((1,2)[0], (2,1)[1]) == (1,1)
because (3,4)[1] == (4,0)[0], we get ((3,4)[0], (4,0)[1]) == (3,0)
In general, Let \(A, B, C\) be sets. Let \(R\) be a relation from \(A\) to \(B\), and let \(S\) be a relation from \(B\) to \(C\), The composition of \(R\) and \(S\), denoted by \(S \circ R\), is the relation from \(A\) to \(C\) given by
\[S \circ R =\{(a,c) \in A \times C: (\exists b \in B)[(a,b) \in R \land (b,c) \in S]\}\]Read more: